TITLE

Solution to Spectroscopy Challenge 4

AUTHOR(S)
Pretsch, E.; Zenobi, R.
PUB. DATE
January 2004
SOURCE
Analytical & Bioanalytical Chemistry;Jan2004, Vol. 378 Issue 1, p15
SOURCE TYPE
Academic Journal
DOC. TYPE
Article
ABSTRACT
The article focuses on the answer and winner to the contest of Analytical Challenge. The signal of the isolated CH2 group appears broadened in the 1H NMR spectrum and shows a triplet splitting in the 13C NMR spectrum. This is due to the coupling with 14N. Usually in the NMR spectra, this coupling is not seen because the quadrupole relaxation of 14N brings about a very short lifetime of its spin states. If however, the electric field gradient around the N atom is negligible, such as in small symmetrical ammonium compounds, the coupling to 14N leads to a splitting of the signal into 3 lines of equal intensity.
ACCESSION #
15125708

 

Related Articles

Share

Read the Article

Courtesy of THE LIBRARY OF VIRGINIA

Sorry, but this item is not currently available from your library.

Try another library?
Sign out of this library

Other Topics